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Use class before defining it in Django model

When I try to sync, I get an error. Menu is not a valid class name.

How can I solve this relationship case:

class MenuItem(model.Models)
    title = models.CharField(max_length=200)
    submenus = models.ManyToManyField(Menu, blank=True, null=True)

class Menu(Container):
    links = models.ManyToManyField(MenuItem)
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2 answers


One of these models has many, many, the other uses Django reverse relationships (https://docs.djangoproject.com/en/dev/topics/db/queries/#following-relationships-backward)

So, how would I set it up:

class Menu(Container):
    links = models.ManyToManyField(MenuItem)

class MenuItem(model.Models)
    title = models.CharField(max_length=200)


Then when I wanted the MenuItem:

menu_item_instance.menu_set.all()
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From the Django book :

If you need to create a relationship on a model that has not yet been, you can use the model name rather than the model of the object itself:

eg:.



class MenuItem(model.Models)
    title = models.CharField(max_length=200)
    submenus = models.ManyToManyField('Menu', blank=True, null=True)
                                      ^    ^

Edit:
As Francis mentions (and as written in the documentation ):

It doesn't matter which model has a ManyToManyField, but you should only put it in one of the models - not both.

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