Accessing a value in a method using *

Question

In a method definition, when *

used like this, what does it mean?

def foo(*)
   ...
end

I understand the following usage:

def foo(*args)
   ...
end

I'm not sure how to access the method parameters in the first case.

+3

Prasad 09 Mar 12 at 21:52

2 answers

In the first case, it simply allows the call with arbitrary arguments and discards them.

The second case assigns any arguments to args

0

James kyburz 09 Mar 12 at 21:56

Matheus moreira · Accepted Answer · 2012-03-09T21:54:23+0000

This means "accept and discard any number of parameters."

Both definitions are technically the same, but without specifying the name of the argument array, you cannot access it.