Llvm g ++ and boost function

I'm trying to undo if the overhead introduced by boost :: function for evaluating math functions is invaluable compared to using it function templates

.

The code for the test I'm using is below.

With traditional g++

overheads, they are boost::function

invaluable:

$ g++ -O3 main.cxx 
$ ./a.out
METHOD              INTEGRAL  TIME TO COMPUTE (SEC)         
Direct              0.379885  3.360000                      
Function template   0.379885  3.380000                      
Boost function      0.379885  3.400000   

      

With llvm-g++

there is a gain of 1.5 for templates function

, but no gain for boost::function

.

$ llvm-g++ -O3 main.cxx
METHOD              INTEGRAL  TIME TO COMPUTE (SEC)         
Direct              0.379885  2.170000                      
Function template   0.379885  2.160000                      
Boost function      0.379885  3.360000    

      

Is it possible to get a gain of 1.5 for boost::function

and llvm-g++

?

#include <boost/function.hpp>
#include <math.h>
#include <stdio.h>

typedef unsigned int UInt;

using namespace std;

//=============================================================================
// chrono
//=============================================================================
class Chrono
{
    clock_t t1_,t2_,dt_;
    public:
        Chrono(){}
        void   start() { t1_=clock(); };
        void   stop()  { t2_=clock(); };
        double diff()  { return ( (double)( t2_ - t1_) ) / CLOCKS_PER_SEC; };
};

//=============================================================================
// function to integrate
//=============================================================================
inline double fct(double x)
{
    return 1. / (1.+exp(x));
}

//=============================================================================
// using direct method
//=============================================================================
double direct(double a, double b, UInt numSamplePoints)
{
    double delta = (b-a) / (numSamplePoints-1);
    double sum = 0.;
    for (UInt i=0; i < numSamplePoints-1; ++i)
        sum += 1. / (1. + exp(a + i*delta));
    return sum * delta;
}

//=============================================================================
// using function template
//=============================================================================
template<double functionToIntegrate(double)>
double integrate(double a, double b, UInt numSamplePoints)
{
    double delta = (b-a) / (numSamplePoints-1);
    double sum = 0.;
    for (UInt i=0; i < numSamplePoints-1; ++i)
        sum += functionToIntegrate(a + i*delta);
    return sum * delta;
}

//=============================================================================
// using Boost function
//=============================================================================
typedef boost::function<double ( double )> fct_type;

class IntegratorBoost {
    public:
    fct_type functionToIntegrate;
    IntegratorBoost(fct_type fct): functionToIntegrate(fct){}
    double integrate(double a, double b, UInt numSamplePoints)
    {
        double delta = (b-a) / (numSamplePoints-1);
        double sum = 0.;
        for (UInt i=0; i < numSamplePoints-1; ++i)
        sum += functionToIntegrate(a + i*delta);
        return sum * (b-a) / numSamplePoints;
    }
};

//=============================================================================
// main
//=============================================================================
int main()
{
    double integral;
    UInt numSamplePoints = 5E07;
    Chrono chrono;

    printf("%-20s%-10s%-30s\n","METHOD","INTEGRAL","TIME TO COMPUTE (SEC)");

    // Direct
    chrono.start();
    integral = direct(0., 1., numSamplePoints);
    chrono.stop();
    printf("%-20s%-10f%-30f\n","Direct",integral,chrono.diff());

    // Function template
    chrono.start();
    integral = integrate<fct>(0., 1.,numSamplePoints);
    chrono.stop();
    printf("%-20s%-10f%-30f\n","Function template",integral,chrono.diff());

    // Boost function
    chrono.start();
    IntegratorBoost intboost(fct);
    integral = intboost.integrate(0.,1.,numSamplePoints);
    chrono.stop();
    printf("%-20s%-10f%-30f\n","Boost function",integral,chrono.diff());
}

      

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1 answer


Without real measure, I'm going to take a chance and argue that using boost::function

(or std::function

from C ++ 11) cannot be as efficient as the other two options.

The reason is that it function

uses type erasure to remove the type of the actual functor being used, which means that it is function

necessary to preserve the actual object that makes the call through the pointer and uses the function calls. On the other hand, in the other two methods, the compiler can inline the logic and remove the shipping cost.



This is actually very similar to the many times mentioned difference in performance of the C library qsort

versus C ++ sort

, where by using a functor the compiler has a better chance of embedding and optimization.

Then another question arises: does this affect your application, and for that you need to measure. Perhaps, in general, I / O cost or any other operation dominates your application and it won't make any difference.

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