How to parse xml from android project resources

I have an XML file (config.xml) in the res / xml folder and I need to parse this XML. I use SAXParser for this. I try like this:

SAXParserFactory factory = SAXParserFactory.newInstance();
SAXParser saxParser = factory.newSAXParser();
DefaultHandler handler = new DefaultHandler() {
          //handler definition...
Uri configUri = Uri.parse("android.resource://myPackageName/" + R.xml.config);
saxParser.parse(configXML.toString(), handler);


But that doesn't work ...

The parse method has the following parameters:

uri Location of parsed content.

dh Use SAXDefaultHandler.

Should I be using a URI or Uri? What is the difference?


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1 answer

I have an XML file (config.xml) in res / xml folder and I need to parse this XML

Call getResources().getXml(R.xml.config)

. You will be given XmlResourceParser

which API will follow XmlPullParser

. As shown in the XmlPullParser

, you complete the code like this:

     XmlResourceParser xpp=getResources().getXml(R.xml.config);
     int eventType = xpp.getEventType();

     while (eventType != XmlPullParser.END_DOCUMENT) {
       if (eventType == XmlPullParser.START_DOCUMENT) {
           // do something
       } else if (eventType == XmlPullParser.START_TAG) {
           // do something
       } else if (eventType == XmlPullParser.END_TAG) {
           // do something
       } else if (eventType == XmlPullParser.TEXT) {
           // do something
      eventType =;



I use SAXParser for this

Even if you can get this to work, it will be ~ 10x slower than using XmlResourceParser




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