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Java XML parse / query

I have this XML structure when I use NodeList nList = doc.getElementsByTagName ("stock"); he gives me back 3 stocks, 2 main stock tags and the one under the armrests. I only want to get the two stocks that are on the top level and ignore anything under the pad tags.

Is it possible in Java to do something like a LINQ query in C #, say, return me items only where the name is "Sony".

Thank!

<city>
   <stock>
     <name>Sony</name>
   </stock>
   <stock>
     <name>Panasonic</name>
     <substocks>
          <stock>
             <name>Panasonic Shop 2</name>
          </stock>
     </substocks>
   </stock>
</city>
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4 answers


I recommend that you use XPath with javax.xml. xpath :

final InputStream is = new FileInputStream('your.xml');

final DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
final DocumentBuilder builder = factory.newDocumentBuilder();
final Document doc = builder.parse(is);
final XPathFactory xPathfactory = XPathFactory.newInstance();
final XPath xpath = xPathfactory.newXPath();
final XPathExpression expr = xpath.compile("/city/stock/name[text()='Sony']");


and then:

final NodeList nl = (NodeList) expr.evaluate(doc, XPathConstants.NODESET);
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Take a look at XPath and its java JXPath implementation . Another possible approach is to parse XML using JAXB and a list of work objects using LambdaJ.



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There is also a dom4j library that has powerful navigation with XPath:

import org.dom4j.Document;
import org.dom4j.io.SAXReader;

SAXReader reader = new SAXReader();
Document document = reader.read("test.xml");
List list = document.selectNodes("/city/stock/name[text()='Sony']");
for (Iterator iter = list.iterator(); iter.hasNext(); ) {
    // TODO: place you logic here
}

More examples here

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Try jcabi-xml (see this blog post ) with one layer:

Collection<XML> found = new XMLDocument("your document here").nodes(
  "/city/stock/name[text()='Sony']"
);
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