What's wrong with this imperative version of the factor function in ocaml?
let impfac i =
let l = ref i in
let result = ref 1 in
let k = ref 2 in
while !k < !l do
result := !result * !k
k:=!k+1
done;
!result
Error message:
let impfac i =
let l = ref i in
let result = ref 1 in
let k = ref 2 in
while !k < !l do
result := !result * !k
k:=!k+1
done;
!result;;
Characters 121-123:
result := !result * !k
^^
Error: This expression is not a function; it cannot be applied
#
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1 answer
result := !result * !k k:=!k+1
You are missing the semicolon at the end of the first line. Because of this, it reads like:
result := !result * (!k k:=!k+1)
i.e. it thinks you are trying to call !k
with k:=!k+1
as its argument.
This is why your editor put the line k := !k+1
farther to the right of the line above it. This should have been the first sign that something was wrong with the syntax.
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