XSLT to remove element value
I need to remove the value from an element, but keep the element itself in the output XML as an empty element.
My input file:
<a>
<b>TEXT1
<c>123</c>
<d>qwe</d>
<e>rty</e>
</b>
<b>TEXT2
<c>345</c>
<d>iop</d>
<e>jkl</e>
</b>
</a>
The output file should contain element c, but the numbers in the element should disappear.
<a>
<b>TEXT1
<c></c>
<d>qwe</d>
<e>rty</e>
</b>
<b>TEXT2
<c></c>
<d>iop</d>
<e>jkl</e>
</b>
</a>
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2 answers
XSLT 1.0
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="c">
<c/>
</xsl:template>
</xsl:stylesheet>
XML output
<a>
<b>TEXT1
<c/>
<d>qwe</d>
<e>rty</e>
</b>
<b>TEXT2
<c/>
<d>iop</d>
<e>jkl</e>
</b>
</a>
Note: <c/>
and are <c></c>
equivalent.
+1
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Even simpler / shorter :
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="c/text()"/>
</xsl:stylesheet>
+3
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