Java: create temporary file and replace with original
I need help creating a file
I've been trying for the last hours with RandomAccessFile and trying to achieve the following logic:
- getting a file object
- creating a temporary file with a similar name (how can I make sure the temp file will be created in the same location as the original one?)
- write to this file
- replace the original file on disk with a temporary one (must be in the original file name).
I'm looking for simple code that does this, preferring RandomAccessFile I just can't seem to solve these few steps correctly.
edited: Ok, so ive enclosed this piece of code my problem is that I can't figure out what the correct steps should be. no file is created and I have no idea how to make this "switch"
File tempFile = null;
String[] fileArray = null;
RandomAccessFile rafTemp = null;
try {
fileArray = FileTools.splitFileNameAndExtension(this.file);
tempFile = File.createTempFile(fileArray[0], "." + fileArray[1],
this.file); // also tried in the 3rd parameter this.file.getParentFile() still not working.
rafTemp = new RandomAccessFile(tempFile, "rw");
rafTemp.writeBytes("temp file content");
tempFile.renameTo(this.file);
} catch (IOException ex) {
ex.printStackTrace();
} finally {
rafTemp.close();
}
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2 answers
try {
// Create temp file.
File temp = File.createTempFile("TempFileName", ".tmp", new File("/"));
// Delete temp file when program exits.
temp.deleteOnExit();
// Write to temp file
BufferedWriter out = new BufferedWriter(new FileWriter(temp));
out.write("Some temp file content");
out.close();
// Original file
File orig = new File("/orig.txt");
// Copy the contents from temp to original file
FileChannel src = new FileInputStream(temp).getChannel();
FileChannel dest = new FileOutputStream(orig).getChannel();
dest.transferFrom(src, 0, src.size());
} catch (IOException e) { // Handle exceptions here}
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