# How does Java step by step evaluate something like this step by step?

Possible duplicate:

What are the rules for evaluation order in Java?

`a = f(b) * - d + e++ + f(e)`

Just wondering how this will go in stages, and where can I find the rules for this?

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SECOND EDIT: My answer appears to be wrong, see Adam Liss's link in the comments to the question (now moved to the question itself, see Possible Duplicate). I leave my answer here for the details that Niklas provided along with my (incorrect) answer to see what prompted the comments.

If I am not mistaken, the evaluation tree is built according to operator precedence order and then evaluated accordingly. The method call should be the first thing to evaluate, since return values may be required in the expression.

EDIT: The estimate (assuming the sums are indeed evaluated from left to right) would look like this (the "intermediate value" called t is the current value after each step):

```
evaluate f(b)
calculate t = f(b) - d
calculate t = t + e (since it e++ and not ++e)
evaluate e++
evaluate f(e)
calculate t = t + f(e)
assignment a = t
```

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