Regex replace in Python: convert named group to integer
When replacing a pattern in a string,
I especially need an integer / long value to match a named group.
Example case and what I've tried:
status = {1:'foo', 23:'bar'}
re.sub(
'<status>(?P<id>\d+)',
status.get(int(r'\g<id>')), # ValueError: invalid literal for int() with base 10: '\\g<id>'
# status.get(int(r'\g<id>'.decode())), # ValueError: invalid literal for int() with base 10: '\\g<id>'
# status.get('%d' % r'\g<id>'), # %d format: a number is required, not str
'Tom ran: from <status>1 to <status>23')
Normal casting works well with original string int(r'22')
, but doesn't it work above?
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1 answer
This should work for you:
re.sub(
'<status>(?P<id>\d+)',
lambda m: status.get(int(m.group('id'))),
'Tom ran: from <status>1 to <status>23')
If repl is a function, it is called for each non-overlapping occurrence of the pattern. The function takes one argument of the matching object and returns the replacement string. @ http://docs.python.org/library/re.html#re.sub
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