Computational expression using zero

Question

When using a computational expression, the first definition works, and the second doesn't work for Zero.

What is the difference between this:

member o.Zero() = 3

and this:

member o.Zero = fun() -> 3

The first is evaluated as unit -> int

and the second is (unit -> int)

. What is the difference?

+3

Paul Nikonowicz 29 Mar 12 at 16:13

1 answer

pad · Accepted Answer · 2012-03-29T16:22:30+0000

If they are limited, there is no difference. However, in a class definition, the first o.Zero

is a method and the second o.Zero

is a property.

Evaluation of an expression expects a method named Zero

; why it didn't work when you provided a property with the same name.