Does this line create global variables?

Question

var first=second=third=fourth=fifth="Hello, ";

I'm not really sure how to test it :)

+3

Yim Mar 30 12 at 16:02

4 answers

Yes, everything except first

is global in this case. You can test your browser console by running

(function() { var x = y = 1; })();
console.log(y); // 1

You might want var y, x = y = 1;

+2

Thomas allen Mar 30 12 at 16:05

First will be local, the rest will be global. See this script from the JS Fiddle .

+2

Aadaam Mar 30 12 at 16:11

Yes, this is to declare your variables first:

var first,second,third,fourth,fifth;
first=second=third=fourth=fifth="Hello, ";

Will do the same, except all the variables will be in the expected scope.

You only have a variable declaration with a name first

and four other variables are used without declaring them, so they are global.

+1

Paulpro Mar 30 12 at 16:07

Rocket hazmat · Accepted Answer · 2012-03-30T16:04:28+0000

first

will be declared as a local variable and the rest will be global.

To fix this, try the following:

var first, second, third, fourth, fifth;
first = second = third = fourth = fifth = "Hello, ";

Or all on one line:

var first, second, third, fourth, fifth = fourth = third = second = first = "Hello, ";