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Extracting a string from a filename

My script accepts a filename in the form R # TYPE.TXT (# is a number, and TYPE is two or three characters). I want my script to give me a TYPE. What should I do to get it? I think I need to use awk and sed.

I am using / bin / sh (which is a must)

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3 answers


you can use awk

$ echo R1CcC.TXT | awk '{sub(/.*[0-9]/,"");sub(".TXT","")}{print}'
CcC

or



$ echo R1CcC.TXT | awk '{gsub(/.*[0-9]|\.TXT$/,"");print}'
CcC

and if sed is really what you want

$ echo R9XXX.TXT | sed 's/R[0-9]\(.*\)\.TXT/\1/'
XXX
+1


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I think this is what you are looking for.

$ echo R3cf.txt | sed "s/.[0-9]\(.*\)\..*/\1/"

cf


If txt is always uppercase and the filename always starts with R, you can do something like.

$ echo R3cf.txt | sed "s/R[0-9]\(.*\)\.TXT/\1/"
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You can only use the shell (depending on the shell it is in bin/sh

:

f=R9ABC.TXT
f="${f%.TXT}"       # remove the extension
type="${f#R[0-9]}"  # remove the first bit
echo "$type"        # ==> ABC
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