Java: Calc x in sin (x)
My question is about angle functions in Java languge programming. if i want to get sin of any double i just use
double variable = Math.sin(x);
but what if sin (x) = 0.324 (or any other random number) and I want to calculate x? How should I do it? Is there any native function for this in java or should I implement my own algorithm to get this value back?
getXForValue(0.324);
public double getXForValue(double val){
// how to calculate ?
return x;
}
Thank.
What you are describing is called the "arcsine" function. It is available in Java as Math.asin () .
You can read the wiki
Use the arcsin function
x = Math.asin(variable)
To calculate sine inversion in Java you can use
Math.asin(double a)
Returns the sine of the arc of a value; the returned angle ranges from -pi / 2 to pi / 2. Check the java docs for a more detailed description
You can use Math.asin(0.324);
to get x value.
Read the Math.asin () javadoc to know what the function returns.
You have to use the inverse function or arcsine. It has the same relationship to sine as division and multiplication.
5 * x = 10;
10 / 5 = x;
Math.sine(x) = 1;
Math.asine(1) = x;
you need to use these Methods, Math.toDegrees
and Math.asin
, in the following order:
double x = 1.0; // in this example 1.0 corresp to sin(90)
double dX = Math.toDegrees(Math.asin(x));
System.out.println(dX);
Remember that the function asin()
returns a result double RADIANS
.