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Java: Calc x in sin (x)

My question is about angle functions in Java languge programming. if i want to get sin of any double i just use

double variable = Math.sin(x);

but what if sin (x) = 0.324 (or any other random number) and I want to calculate x? How should I do it? Is there any native function for this in java or should I implement my own algorithm to get this value back?

getXForValue(0.324);

public double getXForValue(double val){
 // how to calculate ?
 return x;
}

Thank.

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6 answers


What you are describing is called the "arcsine" function. It is available in Java as Math.asin () .



You can read the wiki

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Use the arcsin function



x = Math.asin(variable)
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To calculate sine inversion in Java you can use

Math.asin(double a)

Returns the sine of the arc of a value; the returned angle ranges from -pi / 2 to pi / 2. Check the java docs for a more detailed description

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You can use Math.asin(0.324);

to get x value.

Read the Math.asin () javadoc to know what the function returns.

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You have to use the inverse function or arcsine. It has the same relationship to sine as division and multiplication.

5 * x = 10;
10 / 5 = x;

Math.sine(x) = 1;
Math.asine(1) = x;
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you need to use these Methods, Math.toDegrees

and Math.asin

, in the following order:

double x = 1.0; // in this example 1.0 corresp to sin(90)
double dX = Math.toDegrees(Math.asin(x));

System.out.println(dX);

Remember that the function asin()

returns a result double RADIANS

.

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