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Linux file names and file sharing

I have a list of files named:

file000
file001
file002
file003
...
file1100

How can I match all files greater than 800 but less than 1000? I am using linux bash

thank

Edit

Actually my files are named:
ab869.enc
cp936.enc
g122345.enc
x2022.enc
abc8859-14.enc
aax5601.enc
cp936-1.enc

so the first solution doesn't match the correct files :(

How can I match files with numbers between 800-999?

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5 answers 


*[89][0-9][0-9].enc

Uses Bash's "pathname" (aka "globbing") expansion function to match all files ending in a number between 800 and 999, followed by ".enc". (This is not a regular expression).

For example, using the above expression, you can do this in your script:



mv *[89][0-9][0-9].enc path/to/destination/

If you wanted it to also match a file named "cp850-1.enc", you would need to change the expression:

*[89][0-9][0-9]*.enc
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In a shell, try this:

ls file{801..999}

Files starting with file801

and ending with file999

.



For an explanation see the manual:

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This provides an interesting extension, but cannot be tested without the original files in the directory.

echo [a-z,A-Z]*{801..999}[a-z,A-Z]*.enc

Both sets of brackets must be followed by an asterisk.

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Make a choice.

ls | awk -F'[^0-9]*' '800<$2&&$2<1000'  # assuming no filenames start with number

perl -le'/(\d+)/&&800<$1&&$1<1000&&print for<*>'
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This is close to what you want:

$ ls *{800..999}{,-*}.enc

ab869.enc  abc8859-14.enc  cp936-1.enc  cp936.enc

The problem is that you raise what you abc8859-14.enc

don't want. In this case egrep will be your friend:

$ ls *{800..999}{,-*}.enc | egrep '[^0-9][0-9]{3}(|-.*)\.enc'

If you want to move or copy files, you probably want to wrap this expression in a loop for

(in certain circumstances, you can use xargs rather than a for loop).

 for file in $(ls *{800..999}{,-*}.enc | egrep '[^0-9][0-9]{3}(|-.*)\.enc')
 do
      # copy abc859-14.enc to abc859-14.bak
      basefile=$(basename $file .enc)
      cp $file "$basefile.bak"
 done
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