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Bashrc if: Expression Syntax error

I wrote the following .bashrc:

# .bashrc
# Source global definitions
if [ -f /etc/bashrc ]; then
        . /etc/bashrc
fi

# User specific aliases and functions


function up( )
{
LIMIT=$1
P=$PWD
for ((i=1; i <= LIMIT; i++))
do
    P=$P/..
done
cd $P
export MPWD=$P
}

function back( )
{
LIMIT=$1
P=$MPWD
for ((i=1; i <= LIMIT; i++))
do
    P=${P%/..}
done
cd $P
export MPWD=$P
}

However, after saving when I did source .bashrc

, I got the following error:if: Expression Syntax.

What am I doing wrong? I've googled but to no avail.

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1 answer 


if: Expression Syntax

is not a bash bug. Your shell may not be bash. In fact, as long as if

it stands alone, no error will occur with if

:



$ if [somethingswrong]; then fail; fi # error, then `[` command must have space around it.
-bash: [somethingswrong]: command not found

You can check your shell by repeating $SHELL

and you can check which version of bash with $BASH_VERSION

. (If the latter is not installed, your shell is not bash.)

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