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Match string containing two "needles"

I have a line that looks something like this:

1: u:mads g:folk 2: g:andre u:jens u:joren

what i need is a way (i assume regex) to get for example u: jens and a number (1 or 2) after.

how do i do this in php (preferably with only one function)?

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3 answers


All matches will be found here. If you only want the former, use preg_match

.



<?php
$subject = '1: u:mads g:folk 2: g:andre u:jens u:joren 3: u:jens';
preg_match_all('#(\d+):[^\d]*?u:jens#msi', $subject, $matches);
foreach ($matches[1] as $match) {
    var_dump($match);
}
?>
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You can use the following regex:

(\d+):(?!.*\d+:.*).*u:jens


If the number you want fits into the first capture group. So, if you are using PHP:

$matches = array();
$search = '1: u:mads g:folk 2: g:andre u:jens u:joren';
if (preg_match('/(\d+):(?!.*\d+:.*).*u:jens/', $search, $matches)) {
  echo 'Found at '.$matches[1]; // Will output "Found at 2"
}
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This will parse the string and return an array containing the numeric keys in which the search string was found:

function whereKey($search, $key) {
  $output = array();
  preg_match_all('/\d+:[^\d]+/', $search, $matches);

  if ($matches[0]) {
    foreach ($matches[0] as $k) {
      if (strpos($k, $key) !== FALSE) {
        $output[] = (int) current(split(':', $k));
      }
    }
  }

  return $output;
}

For example:

whereKey('1: u:mads g:folk 2: g:andre u:jens u:joren', 'u:jens')

... will return:

array(1) { [0]=> int(2) }
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