How to stop io.CopyN
2 answers
CopyN
tries to copy N bytes. If you want to copy less than N bytes then don't use CopyN in the first place. I would probably adapt the original code to something like (untested code):
func copyUpToN(dst Writer, src Reader, n int64, signal chan int) (written int64, err error) {
buf := make([]byte, 32*1024)
for written < n {
select {
default:
case <-signal:
return 0, fmt.Errorf("Aborted") // or whatever
}
l := len(buf)
if d := n - written; d < int64(l) {
l = int(d)
}
nr, er := src.Read(buf[0:l])
if nr > 0 {
nw, ew := dst.Write(buf[0:nr])
if nw > 0 {
written += int64(nw)
}
if ew != nil {
err = ew
break
}
if nr != nw {
err = io.ErrShortWrite
break
}
}
if er != nil {
err = er
break
}
}
return written, err
}
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How to close the input file only? io.CopyN
then will return an error and abort.
Here is a demonstration (if you do not work on Linux, replace /dev/zero
and /dev/null
at the equivalent of your operating system!)
package main
import (
"fmt"
"io"
"log"
"os"
"time"
)
func main() {
in, err := os.Open("/dev/zero")
if err != nil {
log.Fatal(err)
}
out, err := os.Create("/dev/null")
if err != nil {
log.Fatal(err)
}
go func() {
time.Sleep(time.Second)
in.Close()
}()
written, err := io.CopyN(out, in, 1E12)
fmt.Printf("%d bytes written with error %s\n", written, err)
}
On startup, it will print something like
9756147712 bytes written with error read /dev/zero: bad file descriptor
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