MIPS Team - Build BEQ

I copied the job image I have on MIPS - Aseembly.

I understand (I think) what is going on in the code before the line:

beq $11, $0, 3

      

        
        
        
      

    

I understand that the code now makes a PC-RELATIVE branch for the address:

PC+4+3*4 

      

        
        
        
      

    

But I don't understand how it goes in this code right here - which next line should be canceled?

I'll make my question clearer:

Row 1: adds 15 to zero, puts it in $a0 register.

Row 2: ANDs $a0 register with 3, puts the result in $a0.

Row 3: ORs $a0 register with 22, puts the result in $a0.

Row 4: shifts $a0 to the left by 5 bits. Result - in $a0.

Row 5: if $a0 equals $a0, go to PC+4+6*24 address. The address is Row 7 which is:

slt $11, $10, $9

      

        
        
        
      

    

Which puts the value 0 in the $ t3 register, because $ 10 = $ 9.

Now I get into ROW 8:

beq $11, $0, 3.

      

        
        
        
      

    

What does line 8 do?

Any help is assigned.

Direct link to my image - click if you can't read it correctly.