MIPS Team - Build BEQ
I copied the job image I have on MIPS - Aseembly.
I understand (I think) what is going on in the code before the line:
beq $11, $0, 3
I understand that the code now makes a PC-RELATIVE branch for the address:
PC+4+3*4
But I don't understand how it goes in this code right here - which next line should be canceled?
I'll make my question clearer:
Row 1: adds 15 to zero, puts it in $a0 register.
Row 2: ANDs $a0 register with 3, puts the result in $a0.
Row 3: ORs $a0 register with 22, puts the result in $a0.
Row 4: shifts $a0 to the left by 5 bits. Result - in $a0.
Row 5: if $a0 equals $a0, go to PC+4+6*24 address. The address is Row 7 which is:
slt $11, $10, $9
Which puts the value 0 in the $ t3 register, because $ 10 = $ 9.
Now I get into ROW 8:
beq $11, $0, 3.
What does line 8 do?
Any help is assigned.
Direct link to my image - click if you can't read it correctly.
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beq $11, $0, 3
means the transition to the third team forward from beq
if $11 == $0
. For example:
beq $11, $0, 3
instruction 1
instruction 2
instruction 3 < the target
the number 3
will be the first sign extension and then added to the program counter $pc
as:
$pc = $pc + 3 * 4
or simply:
$pc = $pc + 3 << 2
4
is that each MIPS instruction is 4 bytes in size.