How to copy character array to another character array in 'c' using pointers and without using string library
How can I copy a character array to another character array in C
using pointers and without using a string library?
I've tried this:
Header file:
char strconcat(char a[100], char b[100]) {
int i=0,j=0;
while(a[i] != '\0'){
i++;
}
while(b[j] != '\0'){
a[i] = b[j];
j++;
i++;
}
return a[100];
}
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3 answers
char *strconcat(char *dst, const char *src)
{
char *bak = dst;
while (*dst) dst++;
while (*dst = *src)
{
dst++;
src++;
}
return bak;
}
Note that there can be no char a[100]
. In C, this notation is automatically converted to char a[]
, which is equivalent char *a
.
You also don't need to compare things with 0. Omitting the comparison will happen by default.
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The first version naively assumes enough space at the destination,
char *
my_strcat(char *destp, char *srcp)
{
if(!destp) return(destp); //check that dest is valid
if(!srcp) return(destp); //check that src is valid
char *dp=destp; //save original destp
while(*dp) { dp++; } //find end of destp
while(*srcp)
{
*dp++ = *srcp++; //copy src to dest, then increment
}
return(destp);
}
The second version allows you to specify the maximum size for the destination,
char *
my_strncat(char *destp, char *srcp, long max)
{
if(!destp) return(destp); //check that dest is valid
if(!srcp) return(destp); //check that src is valid
char *dp=destp; //save original destp
long x=0;
while(*dp && (x<max)) { dp++; ++x; } //find end of destp
while(*srcp && (x<max)) //copy from src while more space in dst
{
*dp++ = *srcp++; ++x; //copy src to dest, then increment
}
*dp = '\0'; //ensure destination null terminated
return(destp);
}
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