Javascript - set spacing for each array value. setinterval, array, foreach

I am trying to get each link multiple intervals. For example: I get the first link, wait 30 seconds, the next link, wait 30 seconds for another link, etc. Here is my code:

var urls = [ 'http://mylink1','http://mylink2','http://mylink3','http://mylink4'];

setInterval(function(){
        urls.forEach(function(entry){
            console.log(entry);
            ajaxd(entry);
            console.log("merge pana aici");
        });
    },30000);

function ajaxd(my_url) {
    $.ajax({
        type : "POST",
        url : my_url,
        success : function(msg) {
            console.log(my_url);
        }
    });
}

      

And the problem is that after 30 seconds I get all the links. Not the first value, wait 30 seconds, next value, etc.

+3


source to share


7 replies


EDIT Updated the code to repeat the loop.



(function() {

  var urls = ['http://mylink1', 'http://mylink2', 
              'http://mylink3', 'http://mylink4'];

  // Start off at the first element.
  var idx = 0;
  var len = urls.length;

  // Do the next link
  function doNext() {
    var entry = urls[idx];

    console.log(idx + ":" + entry);
    //ajaxd(entry);

    idx++;
    console.log([idx, len]);
    if (idx < len) {
      // Don't do anything special
    }  else {
      // Reset the counter
      idx = 0;
    }
    setTimeout(doNext, 300);      }

  // And the code needs kicked off somewhere
  doNext();

}());//end of function 

      

+3


source


In your closure, you use a for loop to query all elements at once.



0


source


The foreach creation will loop through all the values ​​in the array just after the interval.

The best solution is not to iterate ...

eg

var counter = 0;

setInterval(function(){
  if(counter < url.length){
    ajaxd(url[counter]);
    counter++;
  }else
    return;
}, 30000);

      

0


source


You are doing it wrong, try to create a counter every 30 seconds. check this code:

$(document).ready(function(){

    var urls = [ 'http://mylink1','http://mylink2','http://mylink3','http://mylink4'],
        counter = 0;

        obj = {}

    obj.ajaxd = function(my_url) {
        $.ajax({
            type : "POST",
            url : my_url,
            success : function(msg) {
                console.log(my_url);
            }
        });
    }

    obj.leftInterval = setInterval(function(){
        if(urls[counter] != undefined){
            obj.ajaxd(urls[counter]);   
            counter++;
        }else{
            counter = 0;
         }

     },30000);

 });

      

0


source


var urls = ['http://mylink1','http://mylink2','http://mylink3','http://mylink4'],

var request = function(index) {
    $.ajax({
        type : "POST",
        url : urls[index],
        success : function(content) {
            console.log(content);
            if (index + 1 < urls.length) {
                setTimeout(function () {
                    request(index + 1);
                }, 30 * 1000); // 30s
            }
        }
    });
}

request(0);

      

0


source


Use this:

var urls = [ 'http://mylink1','http://mylink2','http://mylink3','http://mylink4'];
urls.reverse();
var interval = setInterval(function(){ 
    if(urls.length == 0){
        clearInterval(interval);
        return;
    }
    var entry = urls.pop();
    console.log(entry);
    ajaxd(entry);
    console.log("merge pana aici");
}, 30000);

      

Note that this will change your array. It will remove items from them until it becomes empty.

EDIT: Based on Andrey's comment, added a return statement after clearInterval :) Thanks.

0


source


If you still want to use forEach to encode the array, you can use it with setTimeout, but not with setInterval .

var urls = ['http://mylink1', 'http://mylink2', 'http://mylink3', 'http://mylink4'],
    interval = 2000, //  = 2s
    increment = 1;

urls.forEach(function(url) {
  var runner = setTimeout(function() {
    // Do your stuff.
    console.log(url);

    clearTimeout(runner);
  }, interval * increment);

  increment = increment + 1;
});

      

0


source







All Articles