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How to get the sizeof of an array in the following case:

I have written the C code as shown below,

#define SOB1 10
#define SOB2 20

char Buffer_1[SOB1];
char Buffer_2[SOB2];


char * CommandArray[2] = {Buffer_1,Buffer_2};

How to get indirect size Buffer_1

and Buffer_2

through CommandArray

? More precisely, I have to know the SOB1 or SOB2 value based on the indexchar * CommandArray[2]

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3 answers


Without saving the information yourself, you can't.



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In this case, you cannot do sizeof

, as the metadata of the array was lost when you started accessing it with a pointer. You will need to use sizeof(Buffer_1)

or sizeof(Buffer_2)

.



Another option (if you don't have access to Buffer_1

and Buffer_2

) would be to store a second size variable equal #define

for each buffer and use that. Since the array does not contain a string, you cannot check \0

or the like either, so you need to be very careful about buffer overflows when using them (another reason for storing a variable size).

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You can just assign it to the pointer. You need to allocate memory with calloc or malloc.

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