Check two conditions in if statement in bash

Question

I have a problem in writing if the operator

var1=`COMMAND | grep <Something>`
if [ -n "$var1" ] && if [[ "$var1" != string ]]; then
    .
    .
    .
fi

I want to write an if statement that checks:

If var1 is not null AND if the string (maybe hello

word) is not in var1 then do stuff.

How can i do this?

+3

MLSC 20 Aug 14 at 12:27

3 answers

Other possibilities:

if [ -n "$var1" -a "$var1" != string ]; then ...

if [ "${var1:-xxx}" != "string" ]; then ...

+4

ooga 20 Aug 14 at 12:55

You should rephrase the condition as follows:

var1=`COMMAND | grep <Something>`
if [ -n "$var1" ] && [[ "$var1" != "string" ]]; then
.
.
.
fi

or equivalent:

if test -n "$var1"  && test "$var1" != "string"
then
...
fi

+1

opalenzuela 20 Aug 14 at 12:29

fedorqui · Accepted Answer · 2014-08-20T12:30:27+0000

Just use something like this:

if [ -n "$var1" ] && [[ ! $var1 == *string* ]]; then
...
fi

See example:

$ v="hello"
$ if [ -n "$v" ] && [[ $v == *el* ]] ; then echo "yes"; fi
yes
$ if [ -n "$v" ] && [[ ! $v == *ba* ]] ; then echo "yes"; fi
yes

The second condition is a variation of what is specified in String contains in bash .