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Why is implicit conversion from <int64_t, int64_t> pair to <int, int> pair allowed?

I noticed some cases where std :: pair would be implicitly converted to std :: pair of a different type without warning, but I can't figure out why. I've looked at the constructors for std :: pair and can't figure it out. Can anyone explain this to me?

Example:

 std::pair<int,int> a = std::pair<int64_t, int64_t>(1,2);

Doesn't give any warnings with clang -Wall -Weverything.

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Constructor

template<class U, class V> pair(const pair<U, V>& p);


allows copying from any pairs, if the first element p

can be converted to the first element of the pair to be built, and the same for the second elements.

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