Cast function pointer to functor in C ++

Question

I have a function pointer type imported from another .hpp file. Something like:

typedef void (*PFN_func)(int i);

I want to create a functor of the same type:

std::function<PFN_func>

But it doesn't work. I don't want a solution like

std::function<void(int)>

Since the definition of a function pointer mt is much more complicated

+3

user972014 09 Sep '14 at 21:00

1 answer

Brian · Accepted Answer · 2014-09-09T21:06:12+0000

You can do it:

std::function<std::remove_pointer<PFN_func>::type>

Removing the pointer from void (*)(int)

gives the type of the function void(int)

.