# Changing matrix elements using a for loop in matlab

I am having a few problems getting MATLAB to do what I want.

Let's say I have a matrix `x = [1 2 3 4; 1 4 4 5; 6 4 1 4]`

I am trying to write code that will go through the matrix and change every 4 to 5, so it changes the input matrix

I've tried several things:

```
while index <= numel(x)
if index == 4
index = 5;
end
index = index + 1;
end
for item = x
if item == 4
item = 5;
end
end
```

The simplest thing I tried was

```
for item = x
if item == 4
item = 5;
end
end
```

I noticed from looking at the artboard that the element value did change, but the x (matrix) value remained the same.

How do I get the result I'm looking for?

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If you just want to change everything `4`

to `5`

, then:

`x(x==4)=5`

`x==4`

will basically result in a boolean matrix with `1`

everywhere been `4`

in `x`

:

```
[0 0 0 1
0 1 1 0
0 1 0 1]
```

We then use a boolean index to only affect the values `x`

where these are `1`

, and change them all to `5`

c.

If you want to do this using a loop (which I highly recommend against), you can do this:

```
for index = 1:numel(x)
if x(index) == 4
x(index) = 5;
end
end
```

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Short answer to achieve what you want:

`x(x==4) = 5`

The answer to the question of why your code doesn't do what you expected: You change `item`

to 5. But this element is a new variable, it does not point to the same element in your matrix `x`

. Hence, the original matrix `x`

remains unchanged.

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