How to plot points on the clock
I have time in seconds since the beginning of the Unix era. I would like to build them on a 24 hour clock. So far my efforts have been
from __future__ import division
import matplotlib.pyplot as plt
import numpy as np
angles = 2*np.pi*np.random.randint(0,864000,100)/86400
ax = plt.subplot(111, polar=True)
ax.scatter(angles, np.ones(100)*1)
plt.show()
This gives the following
However, this is not exactly what I would like.
- How can I place the points on the circle not inside (or at least bring them further from the center)?
- How do I change labels from corners to time?
- How can I get rid of
0.2, 0.4, ...
? - Basically, how can I make it look more like the dots marked on the clock?
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1 answer
from __future__ import division
import matplotlib.pyplot as plt
import numpy as np
from numpy import pi
angles = 2*pi*np.random.randint(0,864000,100)/86400
ax = plt.subplot(111, polar=True)
ax.scatter(angles, np.ones(100)*1)
# suppress the radial labels
plt.setp(ax.get_yticklabels(), visible=False)
# set the circumference labels
ax.set_xticks(np.linspace(0, 2*pi, 24, endpoint=False))
ax.set_xticklabels(range(24))
# make the labels go clockwise
ax.set_theta_direction(-1)
# place 0 at the top
ax.set_theta_offset(pi/2.0)
# plt.grid('off')
# put the points on the circumference
plt.ylim(0,1)
plt.show()
Or, to better use the face of the clock, you could replace the graph with a scatter
graph bar
(the inspiration for this came from this codegolf answer ):
# ax.scatter(angles, np.ones(100)*1, marker='_', s=20)
ax.bar(angles, np.full(100, 0.9), width=0.1, bottom=0.0, color='r', linewidth=0)
Or, to make the bars look more like ticks, you can set bottom=0.89
:
ax.bar(angles, np.full(100, 0.9), width=0.05, bottom=0.89, color='r', linewidth=0)
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