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Calling script from daemon

I am trying to call a script from python-daemon but it doesn't work. this is what I am linking, is it correct?

I also want to pass a random argument to this script, currently I have hardcoded it

import daemon
import time
import subprocess
import os

def interval_monitoring():
    print "Inside interval monitoring"
    while True:
        print "its working"
#         os.system("XYZ.py 5416ce0eac3d94693cf7dbd8") Tried this too but not working
        subprocess.Popen("XYZ.py 5416ce0eac3d94693cf7dbd8", shell=False)
        time.sleep(60)
        print "condition true"




def run():
    print daemon.__file__
    with daemon.DaemonContext():
        interval_monitoring()

if __name__ == "__main__":
    run()
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1 answer


If you haven't made an XYZ.py

executable and added #!/usr/bin/env python

to the top line, then you need to call it through python and not directly. So your line will look something like this:



subprocess.check_output(["python", "XYZ.py", "5416ce0eac3d94693cf7dbd8"])

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