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How to get the FrontMost app - iOS8

I used to use spring framework to get frontmost App, it works fine until ios7 but in iOS8. I am not getting the name of the most recent application. I am using this code.

#define SBSERVPATH "/System/Library/PrivateFrameworks/SpringBoardServices.framework/SpringBoardServices"
#define UIKITPATH "/System/Library/Framework/UIKit.framework/UIKit"
 //To get port
    mach_port_t *p;
    void *uikit = dlopen(UIKITPATH, RTLD_LAZY);
    int (*SBSSpringBoardServerPort)() =
    dlsym(uikit, "SBSSpringBoardServerPort");
    p = (mach_port_t *)SBSSpringBoardServerPort();
    dlclose(uikit);

void *sbserv = dlopen(SBSERVPATH, RTLD_LAZY);

void* (*SBFrontmostApplicationDisplayIdentifier)(mach_port_t* port,char * result) =
    dlsym(sbserv, "SBFrontmostApplicationDisplayIdentifier");
    //Get frontmost application
    char frontmostAppS[256];
    memset(frontmostAppS,sizeof(frontmostAppS),0);
    SBFrontmostApplicationDisplayIdentifier(p,frontmostAppS);
    NSString * frontmostApp=[NSString stringWithFormat:@"%s",frontmostAppS];

Can someone please help me figure it out. or anyone where I am wrong can add light. Thanks in advance.

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2 answers


You probably can't. According to this post , getting the largest app via SBFrontmostApplicationDisplayIdentifier is considered a privacy leak and is blocked in iOS 8.



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If you are in a Jailbroken environment and connect to SpringBoard, you can use SpringBoard _accessibilityFrontMostApplication

to get a link to the frontmost one SBApplication

:

[[SpringBoard sharedApplication] _accessibilityFrontMostApplication]


If it returns nil

, the user is on the home screen.

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