Why won't this simple Java code compile?

Question

I had this question on a software development quiz and am not sure about the rationale behind the answer.

unsigned int x = 1;

while (x> 10) {

System.out.print (x);

x ++;

}

My answer: "Compiling the code, but no way out." Correct answer: "The code does not compile".

Has the compiler tried to work as there are no clear syntax errors?

+3

Louie4 29 Sep 14 at 17:31

3 answers

in valid unsigned keyword in java, but latest java 8 oracle has an explicit api for long type unsigned

https://blogs.oracle.com/darcy/entry/unsigned_api You can look at the above documentation for more details Hope IT can help u

+5

Abhishek chaubey 29 Sep 14 at 17:41

Try running it in an IDE like eclipse. It will show you where the error is.

In this case I am 99% sure that I am unsigned int x = 1;

wrong and should beint x = 1;

+1

starvator 29 Sep 14 at 17:33

Eran · Accepted Answer · 2014-09-29T17:32:41+0000

unsigned int x = 1;

This is not valid syntax in Java.

Change it to

int x = 1;