# How to print the Pythagorean triplet with the largest hypotenuse

I need to find all Pythagorean triples that have a "c" value (where c is a hypotenuse) less than a user-entered integer. I was able to do this, however I also need to print which triplet has the highest "c" value.

```
# include <stdio.h>
int main()
{
int i=1, N, a, b, c;
printf("Please enter an integer number: ");
scanf("%d", &N);
for(c=1; c<N; c++)
{
for(b=1; b<c; b++)
{
for(a=1; a<b; a++)
{
if((a*a)+(b*b)==(c*c))
{
printf("\n%d.(%d,%d,%d)\n", i++, a, b, c);
}
}
}
}
printf("\nThere are %d triples which contain a c<N.\n\n", (i++)-1);
system("PAUSE");
return(0);
}
```

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1 answer

You can have a variable to remember the largest c. Below commented lines are added, take a look:

```
int largest_c = 0; //define it
for(c=1; c<N; c++)
{
for(b=1; b<c; b++)
{
for(a=1; a<b; a++)
{
if((a*a)+(b*b)==(c*c))
{
if (c > largest_c) { //found a bigger one, so remember it
largest_c = c;
}
printf("\n%d.(%d,%d,%d)\n", i++, a, b, c);
}
}
}
}
```

By the way, with a little trick, you can easily speed up your algorithm: anytime you find a ^ 2 + b ^ 2> = c ^ 2, you can skip the rest of it right away for the innermost loop. There is more that can be done to speed up the algorithm.

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