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Get the first character of every word in a string

I am trying to run a program that does the following:

Let's say we have a String

called name

, installed in "Qaru Exchange"

. I want to output to the user "SOE"

with the first characters of each word. I tried using the method split()

but I didn't.

My code:

public class q4 {
    public static void main(String args[]) {
        String x = "michele jones";
        String[] myName = x.split("");
        for(int i = 0; i < myName.length; i++) {
            if(myName[i] == "") {
                String s = myName[i];
                System.out.println(s);
            }              
        }         
    }     
}

I am trying to determine if there are spaces, then I can just take the next index. Can anyone tell me what I am doing wrong?

+3


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8 answers


Try splitting on " "

(space), then get charAt(0)

(first character) of each word and print it like this:



public static void main(String args[]) {
    String x = "Shojibur rahman";
    String[] myName = x.split(" ");
    for (int i = 0; i < myName.length; i++) {
        String s = myName[i];
        System.out.println(s.charAt(0));
    }
}
+3


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String initials = "";
for (String s : fullname.split(" ")) {
  initials+=s.charAt(0);
}
System.out.println(initials);

It works like this:

  • Declare the variable "initials" to store the result
  • Split the full name string by space and iterate over single words
  • Add the first character of each word to the initials

EDIT:

As expected, string concatenation is often inefficient, and StringBuilder is the best alternative if you are working with very long strings:



StringBuilder initials = new StringBuilder();
for (String s : fullname.split(" ")) {
  initials.append(s.charAt(0));
}
System.out.println(initials.toString());

EDIT:

You can just get the string as an array of characters:

char[] characters = initials.toString().toCharArray();
+9


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There are a number of errors in the code:

String [] myName=x.split("");

Are you sure you want to split by ""

(empty string)? You probably wanted to split on spaces:

String [] myName=x.split(" ");

and

if(myName[i]=="")

Never compare strings with ==

in Java, always use .equals

:

if (myName[i].equals(""))
+2


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With Java 8 streams:

String initials = Arrays.stream(str.split(" "))
    .map(s -> s.substring(0, 1))
    .collect(Collectors.joining());
System.out.println(initials);
+2


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You need to shed this space that you cannot divide into "". This means nothing. Another thing that you were wrong was === in string comparison, which is wrong. See How do I compare strings in Java?

public class q4 {
   public static void main(String args[])
   {
       String x="Shojibur rahman";
       String [] myName=x.split(" ");
       for(int i=0; i<myName.length; i++)
       {
           if(!myName[i].equals(""))
           {
               System.out.println(myName[i]);
           }               
       }          
   }     
}
+1


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You are splitting a blank line, not a space "". Your loops don't make much sense either, I'm not sure what you are trying to do.

   String [] myName=x.split(" ");
   for(int i=0; i<myName.length; i++)
   {
       if (!myName[i].isEmpty()) {
          System.out.println(myName[i].charAt(0));
       }              
   }
+1


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Since you don't have thread safety with your program, you can use StringBuilder

. For a long string, I recommend using StringTokenizer

.

+1


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The accepted answer in Java 8:

/**
 * Gets the first character of every word in the sentence.
 *
 * @param string
 * @return
 */
public static String getFirstLetterFromEachWordInSentence(final String string) {
    if (string == null) {
        return null;
    }
    StringBuilder sb = new StringBuilder();
    Arrays.asList(string.split(" ")).forEach(s -> sb.append(s.charAt(0)).append(" "));
    return sb.toString().trim();
}
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