Error: scalar object 'v' requires one element in initializer

Hello,

I have a simple code shown below saved in a file (say stock_portfolio.cxx).

I am trying to compile this as:  g++ stock_portfolio.cxx

but at compile time I get the following error: error: scalar object 'v' requires one element in initializer

The gcc version has: gcc (GCC) 4.1.2 20080704 (Red Hat 4.1.2-52)

#include<iostream>
#include<vector>
int main() {
 std::vector<int>v = {1,2,3,4,5,6};
 //std::vector<string> four_star_stocks;
 for(int i = 0; i < v.size(); ++i){
    std::cout << "Stock S&P: " << v[i] << "\n";
 }
 std::cout << "========================" << "\n";
 std::cout << "Totals   : " << v.size() << "\n";
 return 0;
}

      

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2 answers


list-initialization was only introduced by C ++ in C ++ 11. gcc version 4.1 does not support C ++ 11 (see https://gcc.gnu.org/projects/cxx0x.html )



It is not clear if you are asking a question about a proposed solution / fix or an explanation why your code will not compile.

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Initialize your vector in a loop, for example:

for(int i = 1; i <= 6; ++i)
  v.push_back(i);

      

As cdhowie shows, your version of gcc does not support an initializer list (you need at least g ++ version 4.4,). If you purchase a new one (by adding a flag -std=c++0x

or -std=gnu++0x

), you will see the following:

std::vector<int> v = {1,2,3,4,5,6};



or

If you want to do it with an initializer list, you must use std :: initializer_list like this:

#include <iostream>
#include <vector>
#include <initializer_list>

template <class T>
struct S {
    std::vector<T> v;
    S(std::initializer_list<T> l) : v(l) {
         std::cout << "constructed with a " << l.size() << "-element list\n";
    }
    void append(std::initializer_list<T> l) {
        v.insert(v.end(), l.begin(), l.end());
    }
    std::pair<const T*, std::size_t> c_arr() const {
        return {&v[0], v.size()};  // list-initialization in return statement
                                   // this is NOT a use of std::initializer_list
    }
};

template <typename T>
void templated_fn(T) {}

int main()
{
    S<int> s = {1, 2, 3, 4, 5}; // direct list-initialization
    s.append({6, 7, 8});      // list-initialization in function call

    std::cout << "The vector size is now " << s.c_arr().second << " ints:\n";

    for (auto n : s.v) std::cout << ' ' << n;

    std::cout << '\n';

    std::cout << "range-for over brace-init-list: \n";

    for (int x : {-1, -2, -3}) // the rule for auto makes this ranged for work
        std::cout << x << ' ';
    std::cout << '\n';

    auto al = {10, 11, 12};   // special rule for auto

    std::cout << "The list bound to auto has size() = " << al.size() << '\n';

//    templated_fn({1, 2, 3}); // compiler error! "{1, 2, 3}" is not an expression,
                             // it has no type, and so T cannot be deduced
    templated_fn<std::initializer_list<int>>({1, 2, 3}); // OK
    templated_fn<std::vector<int>>({1, 2, 3});           // also OK
}

      

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