Using pop to remove an element from a 2D array

Question

In the following random array:

a = [[1,2,3,4],
     [6,7,8,9]]

Could you please tell me how to remove an item at a specific position. For example, how to remove a[1][3]

?

I understand this list.pop

is only used for list type DS.

+3

Gaara 24 oct. 14 at 17:57

3 answers

You should use del

to remove an element at a specific index:

>>> a = [[1,2,3,4], [6,7,8,9]]
>>> del a[1][3]
>>> a
[[1, 2, 3, 4], [6, 7, 8]]
>>>

list.pop

should only be used when you need to store the value you just deleted.

+2

iCodez 24 oct. 14 at 17:59

In this case, a[1].remove(9)

removes [1] [3]

-1

ChesterL 24 oct. 14 at 18:03

nathancahill · Accepted Answer · 2014-10-24T17:59:11+0000

Simple, just click on the list item.

>>> a = [[1,2,3,4], [6,7,8,9]]
>>> a[1].pop(3)
>>> a
[[1, 2, 3, 4], [6, 7, 8]]