Split string into non alphanumeric characters with awk

Question

I am trying to get the last substring before an alphanumeric character. For example,

1) beta gamma foo

2) beta gamma% foo

3) beta gamma | --- foo

In all the examples above, I am trying to get "foo" as it is the last substring after splitting into non-alphanumeric characters

So far I have tried

cat file* | awk -F'[^:alnum:]' '{print $NF;}' | less

but this does not give expected results

+3

rockstarjindal 27 oct. '14 at 7:18

1 answer

anubhava · Accepted Answer · 2014-10-27T07:21:14+0000

Your POSIX regex is wrong. Use this command awk

:

awk -F '[^[:alnum:]]' '{print $NF}' file
foo
foo
foo