Create a list of combinations
I would like to create a list of numbers with three values ββand would like to cover every combination from 0 to 3. For example:
0, 0, 0 0, 0, 1 ... 1, 0, 3 1, 1, 3
before 3, 3, 3
.
Is there a better way to do this than using multiple loops?
Here is the code I used:
for i in range (0, 4):
for x in range (0, 4):
for t in range (0, 4):
assign = [i, x, t]
+3
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4 answers
You can use itertools.product
:
>>> from itertools import product
>>> list(product({0, 1, 2, 3}, repeat=3))
[(0, 0, 0), (0, 0, 1), (0, 0, 2), (0, 0, 3), (0, 1, 0), (0, 1, 1), (0, 1, 2), (0, 1, 3), (0, 2, 0), (0, 2, 1), (0, 2, 2), (0, 2, 3), (0, 3, 0), (0, 3, 1), (0, 3, 2), (0, 3, 3), (1, 0, 0), (1, 0, 1), (1, 0, 2), (1, 0, 3), (1, 1, 0), (1, 1, 1), (1, 1, 2), (1, 1, 3), (1, 2, 0), (1, 2, 1), (1, 2, 2), (1, 2, 3), (1, 3, 0), (1, 3, 1), (1, 3, 2), (1, 3, 3), (2, 0, 0), (2, 0, 1), (2, 0, 2), (2, 0, 3), (2, 1, 0), (2, 1, 1), (2, 1, 2), (2, 1, 3), (2, 2, 0), (2, 2, 1), (2, 2, 2), (2, 2, 3), (2, 3, 0), (2, 3, 1), (2, 3, 2), (2, 3, 3), (3, 0, 0), (3, 0, 1), (3, 0, 2), (3, 0, 3), (3, 1, 0), (3, 1, 1), (3, 1, 2), (3, 1, 3), (3, 2, 0), (3, 2, 1), (3, 2, 2), (3, 2, 3), (3, 3, 0), (3, 3, 1), (3, 3, 2), (3, 3, 3)]
>>>
+2
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For this you can use the function itertools.product()
:
from itertools import product
for i, x, t in product(range(4), repeat=3):
print (i, x, t)
Demo:
>>> from itertools import product
>>> for i, x, t in product(range(4), repeat=3):
... print (i, x, t)
...
(0, 0, 0)
(0, 0, 1)
(0, 0, 2)
(0, 0, 3)
(0, 1, 0)
# ... truncated for readability ...
(3, 2, 3)
(3, 3, 0)
(3, 3, 1)
(3, 3, 2)
(3, 3, 3)
+2
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