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Resetting a variable to zero during a loop

I have this code that allows me to take a string and replace all vowels with an ever increasing number.

For example, "abababababababababababa" will give me "0b1b2b3b4b5b6b7b8b9b10b11". I'm trying to store it in such a way that the number, when it has passed 9, resets to zero and starts counting again (so that "0b1b2b3b4b5b6b7b8b9b10b11" reads "0b1b2b3b4b5b6b7b8b9b0b1" instead).

I can't figure out how to do this in a loop, which isn't quite confusing. If there is some way to achieve this that someone doesn't mind disclosing, that would be greatly appreciated.

public static String getNumberString( String s)
{
 String word = s;
 String word1 = word.replaceAll("[AEIOUaeiou]", "@");
 int c = 0;

 String word2 =  word1;
 for( c = 0; c <= word.length(); c++)
 {
       word2 = word2.replaceFirst("@", Integer.toString(c));
 }

 return word2;
}
+3


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8 answers


You can use Modulus of 10 (% 10)

this will return the count after the ninth digit to start over.

public static String getNumberString(String s) {
        String word = s;
        String word1 = word.replaceAll("[AEIOUaeiou]", "@");
        int c = 0;

        String word2 = word1;
        for (c = 0 ; c <= word.length() ; c++) {
            word2 = word2.replaceFirst("@", Integer.toString(c % 10));
        }

        return word2;
    }


Output

0b1b2b3b4b5b6b7b8b9b0b1
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How about using modulo?



word2 = word2.replaceFirst("@", Integer.toString(c % 10));
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As a loop, you can use another variable other than c

, as provided, if you can check when c

will become 9

and reset to 0

.

public static String getNumberString( String s)
{
 String word = s;
 String word1 = word.replaceAll("[AEIOUaeiou]", "@");
 int c = 0;

 String word2 =  word1;
 for(int i = 0; i <= word.length(); i++)
 {
       word2 = word2.replaceFirst("@", Integer.toString(c));
       if(c == 9) {
           c = 0;
       } else {
           c++;
       }
 }

 return word2;
}
+1


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Try using the ten module. It will cycle through because when it reaches a multiple of ten, the modulus will be 0 again.

0


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instead of replacing with c, you can use c % 10

0


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In your loop, you can do

for (c = 0; c <= word.length(); c = (c + 1) % 10) {...}
0


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I would use String.toCharArray()

. You can use % 10

to ensure that it count

turns after the ninth digit. Also, I would use StringBuilder

. Something like,

public static String getNumberString(String str) {
    int count = 0;
    StringBuilder sb = new StringBuilder();
    if (str != null) {
        for (char ch : str.toCharArray()) {
            switch (Character.toLowerCase(ch)) {
            case 'a': case 'e': case 'i': case 'o': case 'u':
                sb.append(count);
                ++count;
                count %= 10;
                // or maybe, count = (count > 9) ? 0 : count;
                break;
            default:
                sb.append(ch);
            }
        }
    }
    return sb.toString();
}

Then you can check it like

public static void main(String[] args) {
    String out = getNumberString("abababababababababababa");
    String expected = "0b1b2b3b4b5b6b7b8b9b0b1";
    System.out.println(out.equals(expected));
}

Output

true
0


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you should use c% 10 instead of c like this code:

word2 = word2.replaceFirst("@", Integer.toString(c % 10));
0


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