Add cylinder to graph
I would like to add a transparent cylinder to my 3D scatter plot. How should I do it?
This is the code I am using to create the graph:
fig = plt.figure(2, figsize=(8, 6))
ax = fig.add_subplot(111, projection='3d')
ax.scatter(X, Y, Z, c=Z,cmap=plt.cm.Paired)
ax.set_xlabel("X")
ax.set_ylabel("Y")
ax.set_zlabel("Z")
plt.xticks()
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3 answers
One possible way is to use plot_surface
. After adapting the solution given in this blog post , then
import matplotlib.pyplot as plt
import numpy as np
from mpl_toolkits.mplot3d import Axes3D
fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')
# Scatter graph
N = 100
X = np.random.uniform(-1, 1, N)
Y = np.random.uniform(-1, 1, N)
Z = np.random.uniform(-2, 2, N)
ax.scatter(X, Y, Z)
# Cylinder
x=np.linspace(-1, 1, 100)
z=np.linspace(-2, 2, 100)
Xc, Zc=np.meshgrid(x, z)
Yc = np.sqrt(1-Xc**2)
# Draw parameters
rstride = 20
cstride = 10
ax.plot_surface(Xc, Yc, Zc, alpha=0.2, rstride=rstride, cstride=cstride)
ax.plot_surface(Xc, -Yc, Zc, alpha=0.2, rstride=rstride, cstride=cstride)
ax.set_xlabel("X")
ax.set_ylabel("Y")
ax.set_zlabel("Z")
plt.show()
I added minimal surface configuration, better can be achieved by referring to the docs .
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I improved on @Greg's answer and made a solid 3D cylinder with top and bottom surface and rewrote the equation so you can translate to x, y and z
from mpl_toolkits.mplot3d import Axes3D
import mpl_toolkits.mplot3d.art3d as art3d
import matplotlib.pyplot as plt
import numpy as np
from matplotlib.patches import Circle
def plot_3D_cylinder(radius, height, elevation=0, resolution=100, color='r', x_center = 0, y_center = 0):
fig=plt.figure()
ax = Axes3D(fig, azim=30, elev=30)
x = np.linspace(x_center-radius, x_center+radius, resolution)
z = np.linspace(elevation, elevation+height, resolution)
X, Z = np.meshgrid(x, z)
Y = np.sqrt(radius**2 - (X - x_center)**2) + y_center # Pythagorean theorem
ax.plot_surface(X, Y, Z, linewidth=0, color=color)
ax.plot_surface(X, (2*y_center-Y), Z, linewidth=0, color=color)
floor = Circle((x_center, y_center), radius, color=color)
ax.add_patch(floor)
art3d.pathpatch_2d_to_3d(floor, z=elevation, zdir="z")
ceiling = Circle((x_center, y_center), radius, color=color)
ax.add_patch(ceiling)
art3d.pathpatch_2d_to_3d(ceiling, z=elevation+height, zdir="z")
ax.set_xlabel('x-axis')
ax.set_ylabel('y-axis')
ax.set_zlabel('z-axis')
plt.show()
# params
radius = 3
height = 10
elevation = -5
resolution = 100
color = 'r'
x_center = 3
y_center = -2
plot_3D_cylinder(radius, height, elevation=elevation, resolution=resolution, color=color, x_center=x_center, y_center=y_center)
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Today I have to do the same in my project about adding a transparent cylinder to the result. This is the code I finally get. Therefore, I share with you guys just for training.
import numpy as np
def data_for_cylinder_along_z(center_x,center_y,radius,height_z):
z = np.linspace(0, height_z, 50)
theta = np.linspace(0, 2*np.pi, 50)
theta_grid, z_grid=np.meshgrid(theta, z)
x_grid = radius*np.cos(theta_grid) + center_x
y_grid = radius*np.sin(theta_grid) + center_y
return x_grid,y_grid,z_grid
import matplotlib.pyplot as plt
from mpl_toolkits.mplot3d import Axes3D
fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')
Xc,Yc,Zc = data_for_cylinder_along_z(0.2,0.2,0.05,0.1)
ax.plot_surface(Xc, Yc, Zc, alpha=0.5)
plt.show()
And you will get this beautiful shape.
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