How to program language independent double.tryparse?
i got string values representing double numbers. (i.e. "1.23"). Always with "."
If you run the code:
double dDouble =0;
string sDemo ="1.23";
double.TryParse(sDemo,out dDouble));
it will return 1.23 in dDouble var.
If I switch to another word with "," like "." .... I get 123.0 as dDouble.
How can I guarantee it will always be 1.23 ...
double dDouble =0;
string sDemo ="1.23";
double.TryParse(sDemo,System.Globalization.NumberStyles.Any,
System.Globalization.CultureInfo.InvariantCulture, out dDouble));
but I'm not sure if this will fix the problem permanently.
I just tried
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10 years ago I would have solved it like this (don't do it):
sDemo = sDemo.Replace(",",".");
Now
// to string
var text = someDouble.ToString(NumberFormatInfo.InvariantInfo);
// and back
var number = double.Parse(text, NumberFormatInfo.InvariantInfo);
The key is to use the same culture. If you are converting values for internal use (for example, passing the value double
as part of the text) - use invariant culture. If, however, you want to display it to the user and then read the user input, then use the same culture anyway: if you don't specify the culture for ToString
, then don't specify it for Parse
, and if you did, then do it again.
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