Correct recursive backtracking algorithm?

My purpose is to find a way to display all the possible ways of reverting changes for a given value, with the values ​​being checked in the file txt

. This must be achieved with Recursive Backtracking or my solution will not be provided. I'll be honest that I completely lost how to code the corresponding algorithm. All I know is that the algorithm works something like this:

 start with empty sets.
 add a dime to one set. 
 subtract '10' from my amount.
 This is a negative number, so I discard that set: it is invalid.
 add a nickel to another (empty) set.
 subtract '5' from my amount.
This equals 2; so I'll have to keep working on this set. 
Now I'm working with sets that already include one nickel.
add a dime to one set.
subtract '10' from my amount.
This is a negative number, so I discard that set: it is invalid.
repeat this with a nickel; I discard this possibility because (2 - 5) is also negative.
repeat this with a penny; this is valid but I still have 1 left.
repeat this whole process again with a starting set of one nickel and one penny, 
   again discarding a dime and nickel, 
   and finally adding a penny to reach an amount of 0: this is a valid set.
Now I go back to empty sets and repeat starting with a nickel, then pennies.

      

The problem is that I have no idea how or where to start, just what needs to be done or if any other solutions are obvious.

This is my code:

UPDATED

import java.io.*;
import java.util.*;
import java.lang.*;

public class homework5 {

 public static int penny = 1;
 public static int nickle = 5;
 public static int dime = 10;
 public static int quarter = 25;
 public static int halfDollar = 50;
 public static int dollar = 100;
 public static int change;

  public static void main(String[] args) throws FileNotFoundException {

    ArrayList<Integer> coinTypes = new ArrayList<Integer>();

    Integer i;
    File f = new File (args[0]);
    Scanner input = new Scanner(f);
       input.nextLine();
       while(input.hasNextInt()) {
               i = input.nextInt();
               coinTypes.add(i);
       }
       change = coinTypes.get(coinTypes.size()-1);
       coinTypes.remove(coinTypes.size()-1);
                System.out.println("Found change"); //used for debugging
                System.out.println("Change: " + change);


    System.out.println(coinTypes);
  }
     boolean findChange(int change, List<Integer> coinTypes,
                     List<Integer> answerCoins) {
        if(change == 0) {
          return true;
        }
        if(change < 0) {
          return false;
        } else {
          for(Integer coin : coinTypes) {
              if(findChange(change - coin, coinTypes, answerCoins)){
                 answerCoins.add(coin);
                 return true;
              }
          }

  List<Integer> answer = new ArrayList<Integer>();
   boolean canFindChange = findChange(change, coinTypes, answer);
    if(canFindChange) {
        System.out.println(answer);
    } else { System.out.println("No change found");
      }
   return false;
  }
}

      

Here is the input file that I scan into

java homework5 hwk5sample1.txt

// Coins available in the USA, given in cents.  Change for $1.43?
1 5 10 25 50 100
143

      

OUTPUT

Found change
Change: 143
[1, 5, 10, 25, 50, 100]

      

So using the numbers in mine coinTypes

ArrayList

, I need a generic code algorithm to show all the possible ways to get, for example 143 ($ 1.43) back with changes, using coins in a file with all pennies is the last way to show this.

Please do not think that I want you to push me the algorithm, I just want to help write, otherwise I will not know anything. Thanks everyone for any answers or help you can give, it means a lot to me! Please let me know if I missed anything or if you need more information.

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1 answer


The example you are going through seems to be mostly correct. The only mistake: again discarding a dime and nickel

which should be again discarding a *penny* and nickel

(but I think it's just a typo.)

To write a recursive backtracking algorithm, it is helpful to think of the recursive call as a solution to a subproblem of the original problem. In one possible implementation of the solution, the pseudocode looks like this:

/**
 * findChange returns true if it is possible to make *change* cents of change
 *     using the coins in coinTypes. It adds the solution to answerCoins.
 *     If it impossible to make this amount of change, then it returns false.
 */
boolean findChange(int change, List<Integer> coinTypes, List<Integer> answerCoins) {
    if change is exactly 0: then we're done making change for 0 cents! return true
    if change is negative: we cannot make change for negative cents; return false
    otherwise, for each coin in coinTypes {
        // we solve the subproblem of finding change for (change - coin) cents
        // using the recursive call.
        if we can findChange(change - coin, coinTypes, answerCoins) {
            // then we have a solution to the subproblem of
            // making (change - coins) cents of change, so:
            - we add coin to answerCoins, the list of coins that we have used
            - we return true // because this is a solution for the original problem
        }
    }
    //if we get to the next line, then we can't find change for any of our subproblems
    return false
}

      



We will call this method as follows:

List<Integer> answer = new ArrayList<Integer>();
boolean canFindChange = findChange(change, coinTypes, answer);
if(canFindChange) {
    System.out.println(answer); // your desired output.
}
else {
    System.out.println("Can't find change!");
}

      

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