How to make this F # code more compact

let a = fun x -> x |> f |> g

      

        
        
        
      

    

equivalent to

let a x = x |> f |> g

      

        
        
        
      

    

It sounds like you want to create two functions f

and g

to create a new function a

. You can use operator >>

to create functions. You can write:

let a = f >> g

      

        
        
        
      

    

If f

they g

are generic functions, they will not compile due to the limitations of F # values . In this case, you need to add type annotations:

let a<'a> : ('a -> 'a) = f >> g