Removing multiple stubs using putchar and getchar in C

Problem: Write a program that receives text input with getchar()

and outputs a string by removing multiple spaces.

This is how I wrote the pseudocode:

While each input character is received before reaching EOF, do the following:
     1) if character is non-blank, print it out
     2) otherwise:
         a. print out the blank
         b. do nothing untill the next non-blank character 
     3) if a non-blank character is reached, go back to 1)

      

I tried to implement the algorithm as such:

#include <stdio.h>
/* replaces multiple blanks with a single blank */
main(){
    char c;
    while((c= getchar())!=EOF){
        if (c != ' ')
            putchar(c);
        else {
            putchar(c);
            while(c == ' ')
                ;
        }
    }   
}

      

When the line contains spaces, it stops. I'm not sure how to debug it. I think the problem is with my second while

one and the program ends up in an infinite loop rather than waiting for new characters.

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5 answers


#include <stdio.h>
/* replaces multiple blanks with a single blank */
main(){
    int c; // thanx chux
    while((c= getchar())!=EOF){
        if (c != ' ')
            putchar(c);
        else {
            putchar(c);
            while((c= getchar())!=EOF)
                if (c!=' ')
                {
                    putchar(c);
                    break;
                }
        }
    }   
}

      



Lately, you haven't read characters from stdin by calling an endless loop comparing the last red character to the previous getchar ().

+3


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The anonymous answer works, but there is a simpler algorithm that also works:

While there is input remaining:
    Read a character.
    If the current and previous characters aren't both blank:
        Print the current character.

      



In C:

#include <stdio.h>

int main() {
    int prev = EOF, c;
    while ((c = getchar()) != EOF) {
        if (c != ' ' || prev != ' ')
            putchar(c);
        prev = c;
    }
    return 0;
}

      

+2


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#include <stdio.h>

int main(void){
    int c;
    while((c = getchar())!=EOF){
        if (c != ' ')
            putchar(c);
        else {
            putchar(c);
            while((c = getchar()) == ' ')
                ;
            ungetc(c, stdin);//go back 1
        }
    }
    return 0;
}

      

+1


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This worked for me.

#include <stdio.h>
#include <stdlib.h>

int main()
{
    int c;
    int space = 0;

    while ((c = getchar())!= EOF){

            if (c != ' '){
                putchar(c);
            }else{
                if(space == ' '){
                    continue;
                }else{
                    putchar(c);
                }
            }
            space = c;
    }
    return 0;
}

      

0


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Your program has several problems:

  • the prototype for main()

    must include the return type int

    .

  • c

    must be defined as int

    so that you can correctly distinguish EOF

    from all valid byte values โ€‹โ€‹returned getchar()

    .

  • after you identify a blank character, you must continue reading characters and skip subsequent spaces.

  • technically blank characters include the space character ' '

    and the tab character '\t'

    . You must use isblank()

    from <ctype.h>

    and modify your program to skip subsequent blanks.

Here's a modified version:

#include <ctype.h>
#include <stdio.h>

/* replaces multiple blanks with a single blank */
int main(void) {
    int c;
    while ((c = getchar()) != EOF) {
        putchar(c);
        if (isblank(c)) {
            while (isblank(c = getchar())
                continue;
            if (c == EOF)
                break;
            putchar(c);
        }
    }
    return 0;
}

      

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