Syntax error whenever I try to use sys.stderr
I have a standard error problem, when I try to use it, my computer gives me a syntax error that I cannot explain.
So this is my code:
import sys
def main(argv):
if len(argv) != 3:
print("Usage: python walk.py n l", file=sys.stderr)
else:
l = argv[2]
n = argv[1]
print("You ended up", simuleer(n,l), "positions from the starting point.")
if __name__ == "__main__":
main(sys.argv)
And that's my fault
MacBook-Air-van-Luuk:documents luuk$ python walk.py 5 1 2
File "walk.py", line 21
print("Usage: python walk.py n l", file=sys.stderr)
^
I hope someone can explain to me why this is happening, thanks in advance!
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You think you're using Python 3.x, but it's actually Python 2.x. On most systems, python
executable means Python 2.x.
print
is not a function in Python 2.x and cannot be used this way, causing a syntax error.
You should be looking for a way to run Python 3.x.
In this particular case, you can also use , which will make the code compatible with both versions.from __future__ import print_function
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