Read hierarchical (tree) XML into pandas framework while preserving hierarchy

I have an XML document that contains a hierarchical tree structure, see example below.

The document contains several tags <Message>

(I just copied one of them for convenience).

Everyone <Message>

has some associated data ( id

, status

, priority

) on their own.

Additionally, each <Message>

can contain one or more child elements <Street>

, which again have some relevant data ( <name>

, <length>

).

Also, everyone <Street>

can have one or more children <Link>

, which again have their respective data ( <id>

, <direction>

).

Sample XML Document:

<?xml version="1.0" encoding="ISO-8859-1"?>
<Root xmlns="someNamespace">
<Messages>
<Message id='12345'>
   <status>Active</status>
   <priority>Low</priority>
   <Area>
    <Streets>
     <Street>
      <name>King Street</name>
      <length>Short</length>
       <Link>
        <id>75838745</id>
        <direction>North</direction>
       </Link>
       <Link>
        <id>168745</id>
        <direction>South</direction>
       </Link>
       <Link>
        <id>975416</id>
        <direction>North</direction>
       </Link>
     </Street>
     <Street>
      <name>Queen Street</name>
      <length>Long</length>
       <Link>
        <id>366248</id>
         <direction>West</direction>
       </Link>
       <Link>
        <id>745812</id>
         <direction>East</direction>
       </Link>
     </Street>
    </Streets>
   </Area>
</Message>
</Messages>
</Root>

      

Parsing XML with Python and storing the relevant data in variables is not a problem - I can use, for example, a library lxml

and either read the whole document, or execute some expressions xpath

to get the corresponding fields, or read it line by line using the iterparse

.

However, I would like to put the data in a pandas framework while keeping the hierarchy in it. The goal is to query for individual messages (for example, booleans like if status == Active then get the Message with all its streets and its streets' links

) and get all the data related to a particular message (its streets and links to its streets). What is the best way to do this?

I've tried different approaches but ran into all the problems.

If I create one dataframe row for each XML row that contains information, and then set MultiIndex to [MessageID, StreetName, LinkID]

, I end up with an index with a lot NaN

in it (which is usually not recommended) as I MessageID

don't know your children streets

and links

. Also, I would not know how to select some sub-dataset by boolean state instead of only getting individual rows without its children.

When you do GroupBy on [MessageID, StreetName, LinkID]

, I don't know how to return (like MultiIndex) the dataframe from the pandas GroupBy object, since there is nothing to do here (no / std / sum / whatsoever value, the values ​​must remain the same).

Any suggestions how this could be handled efficiently?

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I finally managed to solve the problem as described above and here's how to do it.

I have expanded the above XML document to include two messages instead of one. This is how it looks like a valid Python string (it can also be loaded from a file):

xmlDocument = '''<?xml version="1.0" encoding="ISO-8859-1"?> \
<Root> \
<Messages> \
<Message id='12345'> \
   <status>Active</status> \
   <priority>Low</priority> \
   <Area> \
    <Streets> \
     <Street> \
      <name>King Street</name> \
      <length>Short</length> \
       <Link> \
        <id>75838745</id> \
        <direction>North</direction> \
       </Link> \
       <Link> \
        <id>168745</id> \
        <direction>South</direction> \
       </Link> \
       <Link> \
        <id>975416</id> \
        <direction>North</direction> \
       </Link> \
     </Street> \
     <Street> \
      <name>Queen Street</name> \
      <length>Long</length> \
       <Link> \
        <id>366248</id> \
         <direction>West</direction> \
       </Link> \
       <Link> \
        <id>745812</id> \
         <direction>East</direction> \
       </Link> \
     </Street> \
    </Streets> \
   </Area> \
</Message> \
<Message id='54321'> \
   <status>Inactive</status> \
   <priority>High</priority> \
   <Area> \
    <Streets> \
     <Street> \
      <name>Princess Street</name> \
      <length>Mid</length> \
       <Link> \
        <id>744154</id> \
        <direction>West</direction> \
       </Link> \
       <Link> \
        <id>632214</id> \
        <direction>South</direction> \
       </Link> \
       <Link> \
        <id>654785</id> \
        <direction>East</direction> \
       </Link> \
     </Street> \
     <Street> \
      <name>Prince Street</name> \
      <length>Very Long</length> \
       <Link> \
        <id>1022444</id> \
         <direction>North</direction> \
       </Link> \
       <Link> \
        <id>4474558</id> \
         <direction>South</direction> \
       </Link> \
     </Street> \
    </Streets> \
   </Area> \
</Message> \
</Messages> \
</Root>'''

      

To parse the XML hierarchical structure into a flat pandas framework, I used the Python ElementTree method iterparse

, which provides a SAX-like interface to iterate through the XML document in turn and fire events if certain XML tags are triggered or end.

For each parsed XML string, this information is stored in a dictionary. There are three dictionaries in use: one for each dataset that belongs to each other in some way (message, street, link), and this must be stored in its own dataframe string later. When all the information in one such line is collected, the dictionary is added to the list, which stores all the lines in the appropriate order.

This is what parsing XML looks like (see inline comments for further explanation):

# imports
import xml.etree.ElementTree as ET
import pandas as pd

# initialize parsing from Bytes buffer
from io import BytesIO
xmlDocument = BytesIO(xmlDocument.encode('utf-8'))

# initialize dictionaries storing the information to each type of row
messageRow, streetRow, linkRow = {}, {}, {}

# initialize list that stores the single dataframe rows
listOfRows = []

# read the xml file line by line and throw signal when specific tags start or end
for event, element in ET.iterparse(xmlDocument, events=('start', 'end')):

    ##########
    # get all information on the current message and store in the appropriate dictionary
    ##########

    # get current message id attribute
    if event == 'start' and element.tag == 'Message':
        messageRow = {} # re-initialize the dictionary for the current row
        messageRow['messageId'] = element.get('id')

    # get current message status
    if event == 'end' and element.tag == 'status':
        messageRow['status'] = element.text

    # get current message priority
    if event == 'end' and element.tag == 'priority':
        messageRow['priority'] = element.text

    # when no more information on the current message is expected, append it to the list of rows
    if event == 'end' and element.tag == 'priority':
        listOfRows.append(messageRow)

    ##########
    # get all information on the current street and store in row dictionary
    ##########

    if event == 'end' and element.tag == 'name':
        streetRow = {} # re-initialize the dictionary for the current street row
        streetRow['streetName'] = element.text

    if event == 'end' and element.tag == 'length':
        streetRow['streetLength'] = element.text

    # when no more information on the current street is expected, append it to the list of rows
    if event == 'end' and element.tag == 'length':

        # link the street to the message it belongs to, then append
        streetRow['messageId'] = messageRow['messageId']
        listOfRows.append(streetRow)

    ##########
    # get all information on the current link and store in row dictionary
    ##########

    if event == 'end' and element.tag == 'id':
        linkRow = {} # re-initialize the dictionary for the current link row
        linkRow['linkId'] = element.text

    if event == 'end' and element.tag == 'direction':
        linkRow['direction'] = element.text

    # when no more information on the current link is expected, append it to the list of rows
    if event == 'end' and element.tag == 'direction':

        # link the link to the message it belongs to, then append
        linkRow['messageId'] = messageRow['messageId']
        listOfRows.append(linkRow)

      

listOfRows

is now a list of dictionaries, in which each dictionary stores information to be placed on one line of the data frame. Creating a DataFrame with this list as the data source can be done with

# create dataframe from list of rows and pass column order (would be random otherwise)
df = pd.DataFrame.from_records(listOfRows, columns=['messageId', 'status', 'priority', 'streetName', 'streetLength', 'linkId', 'direction'])
print(df)

      

and gives the "raw" dataframe:

   messageId    status priority       streetName streetLength    linkId  \
0      12345    Active      Low              NaN          NaN       NaN   
1      12345       NaN      NaN      King Street        Short       NaN   
2      12345       NaN      NaN              NaN          NaN  75838745   
3      12345       NaN      NaN              NaN          NaN    168745   
4      12345       NaN      NaN              NaN          NaN    975416   
5      12345       NaN      NaN     Queen Street         Long       NaN   
6      12345       NaN      NaN              NaN          NaN    366248   
7      12345       NaN      NaN              NaN          NaN    745812   
8      54321  Inactive     High              NaN          NaN       NaN   
9      54321       NaN      NaN  Princess Street          Mid       NaN   
10     54321       NaN      NaN              NaN          NaN    744154   
11     54321       NaN      NaN              NaN          NaN    632214   
12     54321       NaN      NaN              NaN          NaN    654785   
13     54321       NaN      NaN    Prince Street    Very Long       NaN   
14     54321       NaN      NaN              NaN          NaN   1022444   
15     54321       NaN      NaN              NaN          NaN   4474558   

   direction  
0        NaN  
1        NaN  
2      North  
3      South  
4      North  
5        NaN  
6       West  
7       East  
8        NaN  
9        NaN  
10      West  
11     South  
12      East  
13       NaN  
14     North  
15     South  

      

We can now represent the columns of interest (messageId, streetName, linkId) as MultiIndex on this dataframe:

# set the columns of interest as MultiIndex
df = df.set_index(['messageId', 'streetName', 'linkId'])
print(df)

      

which gives:



                                      status priority streetLength direction
messageId streetName      linkId                                            
12345     NaN             NaN         Active      Low          NaN       NaN
          King Street     NaN            NaN      NaN        Short       NaN
          NaN             75838745       NaN      NaN          NaN     North
                          168745         NaN      NaN          NaN     South
                          975416         NaN      NaN          NaN     North
          Queen Street    NaN            NaN      NaN         Long       NaN
          NaN             366248         NaN      NaN          NaN      West
                          745812         NaN      NaN          NaN      East
54321     NaN             NaN       Inactive     High          NaN       NaN
          Princess Street NaN            NaN      NaN          Mid       NaN
          NaN             744154         NaN      NaN          NaN      West
                          632214         NaN      NaN          NaN     South
                          654785         NaN      NaN          NaN      East
          Prince Street   NaN            NaN      NaN    Very Long       NaN
          NaN             1022444        NaN      NaN          NaN     North
                          4474558        NaN      NaN          NaN     South

      

Even though the overall index NaN

is not counted in the index, I don't see any problem with this for this utility.

Finally, to get the desired effect of accessing single posts using messageId

, including all of its "child" streets and links, the MultiIndexed framework must be grouped by the outermost index level:

# group by the most outer index
groups = df.groupby(level='messageId')

      

Now you can, for example, bypass all messages (and do everything with them) with

# iterate over all groups
for key, group in groups:
    print('key: ' + key)
    print('group:')
    print(group)
    print('\n')

      

which returns

key: 12345
group:
                                 status priority streetLength direction
messageId streetName   linkId                                          
12345     NaN          NaN       Active      Low          NaN       NaN
          King Street  NaN          NaN      NaN        Short       NaN
          NaN          75838745     NaN      NaN          NaN     North
                       168745       NaN      NaN          NaN     South
                       975416       NaN      NaN          NaN     North
          Queen Street NaN          NaN      NaN         Long       NaN
          NaN          366248       NaN      NaN          NaN      West
                       745812       NaN      NaN          NaN      East


key: 54321
group:
                                     status priority streetLength direction
messageId streetName      linkId                                           
54321     NaN             NaN      Inactive     High          NaN       NaN
          Princess Street NaN           NaN      NaN          Mid       NaN
          NaN             744154        NaN      NaN          NaN      West
                          632214        NaN      NaN          NaN     South
                          654785        NaN      NaN          NaN      East
          Prince Street   NaN           NaN      NaN    Very Long       NaN
          NaN             1022444       NaN      NaN          NaN     North
                          4474558       NaN      NaN          NaN     South

      

or you can access specific messages messageId by returning a string containing the messageId, along with all highlighted streets and links:

# get groups by key
print('specific group only:')
print(groups.get_group('54321'))

      

gives

specific group only:
                                     status priority streetLength direction
messageId streetName      linkId                                           
54321     NaN             NaN      Inactive     High          NaN       NaN
          Princess Street NaN           NaN      NaN          Mid       NaN
          NaN             744154        NaN      NaN          NaN      West
                          632214        NaN      NaN          NaN     South
                          654785        NaN      NaN          NaN      East
          Prince Street   NaN           NaN      NaN    Very Long       NaN
          NaN             1022444       NaN      NaN          NaN     North
                          4474558       NaN      NaN          NaN     South

      

Hope this is helpful to someone someday.

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