Strange result with simple regex

Question

I am working on regex right now and am experiencing strange behavior:

The following regex takes Q-123456-789

orQ-123456-789

params: '^\\q\\-\\d{6}\\-\\d{3}$|^\\Q\\-\\d{6}\\-\\d{3}$'

The following regex accepts R-123456-789

but does notR-123456-789

params: '^\\r\\-\\d{6}\\-\\d{3}$|^\\R\\-\\d{6}\\-\\d{3}$'

(I just replaced q

with r

and q

with r

)

+3

javascript regex

Bronzato Dec 18 14 at 12:37

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3 answers

\r

matches a carriage return (0x0D is a non-printable character), not a character r

. whereas it \q

matches a character q

.

If you want to combine r

, or r

simply replace it in a character class: ^[rR]

.

0

Maroun Dec 18 14 at 12:40

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Try [r]

for an exact match instead of \r

for the expected result

Try the following:

^[rR]-\d{6}\-\d{3}$

Use https://regex101.com/#javascript for testing

0

Manwal Dec 18 14 at 12:42

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anubhava · Accepted Answer · 2014-12-18T12:41:04+0000

Because:

\r

matches a carriage return

but \q

only matches a literal q

.

Your regex is using redundant escaping, it should be without\\

ie

"^[qQ]-\\d{6}-\\d{3}$"

OR

"^[rR]-\\d{6}-\\d{3}$"