Differences between procedures with and without brackets?

Question

(define (procedere1) (lambda () 2))
(define procedure2 (lambda () 2))

Both of them can be compiled. But I am confused about the difference between the above two procedures.

+3

Charq Lou Dec 31. '15 at 7:27

2 answers

Generally

(define (name arg1 arg2 arg3 ...)
  body)

is shorthand for

(define name
  (lambda (arg1 arg2 arg3 ...) 
    body))

+2

Barmar Dec 31. 15 at 19:28

Chris jester-young · Accepted Answer · 2014-12-31T07:39:05+0000

The first is a procedure that returns a procedure. The second is a procedure that returns the number 2.

In particular, the first one is equivalent to the following:

(define procedure1
  (lambda ()
    (lambda () 2)))