How can I get unique results using grep?
The script below is part of the logic I want to implement as part of a jenkins job. I am trying to write a shell script.
I am using grep command to recursively find a specific line . An example of the result that grep returns looks like this:
./src/test/java/com/ABC/st/test/pricing/Test1.java: @Tags ({"B-05256"})
./src/test/java/com/ABC/st/test/pricing/Test1.java: @MapToVO (storyID = "B-05256: prices in ST")
./src/test/java/com/ABC/st/test/pricing/Test1.java: @Tags ({"B-05256"})
./src/test/java/com/ABC/st/test/pricing/Test2.java: @Tags ({"B-05256"})
./src/test/java/com/ABC/st/test/pricing/Test2.java: @MapToVO (storyID = "B-05256: Lowest Price of the Season")
./src/test/java/com/ABC/st/test/pricing/Test2.java: @Tags ({"B-05256"})
I want to extract unique file paths like:
/src/test/java/com/ABC/st/test/pricing/Test1.java
/src/test/java/com/ABC/st/test/pricing/Test2.java
and then use each unique path in maven command. So:
-
How can I extract the unique file paths from the result set given by the grep command?
-
How do I start a loop like a thing where on each iteration I execute the mvn command with a unique file path?
If you only want the name of the corresponding files, grep
has a command line switch for that:
-l, --files-with-matches
Suppress normal output; instead print the name of each input file from which output
would normally have been printed. The scanning will stop on the first match. (-l is
specified by POSIX.)
Draw text in
sed 's/:.*//' | sort -u | while read path
do
echo now execute your command using "$path"
done
This flag is -l
for grep
for.
-l, --files-with-matches
Suppress normal output; instead, print the name of each input file from which the output would normally be printed. Scanning will stop at the first match. (-l is specified by POSIX.)