C ++ error: expected type-specifier
When I try to compile this simple linked list testing program using the command
g++ -o SLLtest SLLtester.cpp intSLList.o
I am getting the error:
SLLtester.cpp: In function ‘int main()’:
SLLtester.cpp:4:27: error: expected type-specifier
SLLtester.cpp:4:27: error: cannot convert ‘int*’ to ‘intSLList*’ in initialization
SLLtester.cpp:4:27: error: expected ‘,’ or ‘;’
I'm missing something simple, but I'm not sure what. Compiling the header and linked list definitions without issue. Three files are included.
//intSLList.hh
#ifndef INT_LINKED_LIST
#define INT_LINKED_LIST
class intSLList {
public:
intSLList(){head=tail=0;}
void Print();
void AddToHead(int);
void AddToTail(int);
int RemoveFromHead();
int RemoveFromTail();
protected:
struct Node {
int info;
Node *next;
Node(int e1, Node *ptr = 0) {info = e1; next = ptr;}
} *head, *tail, *tmp;
int e1;
};
#endif
And definitions:
//intSLList.cpp
#include "intSLList.hh"
#include <iostream>
void intSLList::AddToHead(int e1){
head = new Node(e1,head);
if (!tail)
tail = head;
}
void intSLList::AddToTail(int e1){
if (tail) {
tail->next = new Node(e1);
tail = tail->next;
}
else
head = tail = new Node(e1);
}
int intSLList::RemoveFromHead(){
if (head){
e1 = head->info;
tmp = head;
if (head == tail)
head = tail = 0;
else
head = head->next;
delete tmp;
return e1;
}
else
return 0;
}
int intSLList::RemoveFromTail(){
if (tail){
e1 = tail->info;
if (head == tail){
delete head;
head = tail = 0;
}
else {
for ( tmp = head; tmp->next != tail; tmp = tmp->next);
delete tail;
tail = tmp;
tail->next = 0;
}
return e1;
}
else return 0;
}
void intSLList::Print(){
tmp = head;
while( tmp != tail ){
std::cout << tmp->info << std::endl;
tmp = tmp->next;
}
}
And finally, the main function:
#include "intSLList.hh"
int main(){
intSLList* mylist = new intSLList::intSLList();
for ( int i = 0; i < 10; i++ ){
mylist->AddToTail(i);
}
mylist->Print();
}
Thanks for the help.
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2 answers
intSLList* mylist = new intSLList::intSLList();
It is not right. When we write new intSLList()
, we are not "calling the constructor" - just by naming the type - and hence the fully qualified constructor name (as intSLList::intSLList
) is incorrect.
So:
intSLList* mylist = new intSLList();
You don't need dynamic placement anyway:
#include "intSLList.hh"
int main()
{
intSLList mylist;
for (int i = 0; i < 10; i++) {
mylist.AddToTail(i);
}
mylist.Print();
}
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