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How do you find the last occurrence of the template using string.find?

I was trying to find out if I can find the last occurrence of the pattern instead of the first using string.fing Eg: in the string "AAAAABBB" I want to find the position of the last "A" isntead of the first.

Is it possible?

thank

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2 answers


Try using an empty capture:

str = "123456AAA7890AAABBBB"
print(str:match(".*()A"))


If you need to use string.find

, try this:

local _,p = str:find(".*A")
print(p)
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local str = "123456AAA7890AAABBBB"
local s, e = str:find("A[^A]*$")

print(s)
print(str:sub(s))

Alternatively reverse the line and use a simpler call string.find

.



local str = "123456AAA7890AAABBBB"
local revstr = str:reverse()
local ind = revstr:find("A")

print(#revstr - ind + 1)
print(str:sub(#revstr - ind + 1))
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